Question

設集合M={x|(x+3)(x-2)<0}，N ={x|1≤x≤3},則M∩N =

1. A.
   [1,2)
2. B.
   [1,2]
3. C.
   ( 2,3]
4. D.
   [2,3]

Answer 1

A
M={x|(x+3)(x-2)<0}=(-3,2), N ={x|1≤x≤3}故M∩N =[1,2)。